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PLANS 500 Big Thompson Ave Framing Mech Duct Work 2005
/ ___________ ARCHITECTS SUPPLEMENTAL INSTRUCTIONS PROJECt:AROflTECIS SUPPLEMENTAL Town of Estes Park Visitor Information Center INSIRUCFION NO:8 500 Big Thompson Avenue Estes Park,CO 80517 OWNER:ARGIITECT: Town of Estes Park Basis Architecture P.C. TO: Dailman Construction Company CONTRACT DATED: June 27th,2005 The Work shall be carried out in accordance with the following supplemental instructions issued in aaordance with the Contract Documents without change in Contract Sum or Contract Time. Proceeding with the Work in accordance with th ktructions indicates iw admdedgement that there will be no change in theConbact SumcrCo*iactTmie.Iftherew bean inctk Contract Sum or Contract Time,please inform the Architect in writing within seven (7)days. Description: Provide franing per the attached AX drawings to provide space for mechanical ductwork. Attachments:AX-20 through AX-22 ISSUED BY:1:: Matthew Heiser Date Basis Architecture P.C. I I I I I I I I . I I I I I I I I I I I I 1. 1 1 I I I I •i I I I I I I I I I I I I I II I I I I I I I I I I I I I I I I I I I l I I I I I I I I I I I I I I I I I I II I I I I I I I I I I I I I I I I I I I II I I I I I I I I I I I I I I I I I I I L’ 1 I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I\ — ’ % . I I I I I I I I I I I I I I I I I I I’ I I I I I 1i i i i i i i i i : : I ki r j r i r I I I IN F L L OP E N I N 3 : : : ‘ “ __ _ _ _ _ _ _ _ _ _ I IW I T I 4 RF P I JO I T I I I I I I i i iH E A E E R i ’ \ i i ,. i , I I i I I I I i i i i i iA S i . r R A W1’i i i i if ” I I I I I I I I I I I / ij l i i I I I I I I I I I j_ 4 D D k 2 ) .1 48 VL _ J J \j I I ‘ ‘ I I i i I I HE D E , F. U S F IA I j I I I ‘ IM q ’ S O J II J 3 5 1 1 _J “L I 1 1 I AC E Mb U N T HN G E l j I +- - I I I I I I I I I I I I I I I I I I Il l I I I 1 2n d Fl o o r Fr a m i n g 1/ 4 1 1 = 1 10fl nd Fl o o r Fr a m i n g 3h e e t No : AX - 2 0 CI 2 cI ) vo x : 97 0 . 5 8 6 . 9 1 4 0 fa x : 97 0 . 5 8 6 . 9 1 4 9 ba s i s _ a r c h @ a i r b i t s . c o m © BA S I S Ar c h i t e c t u r e , P. C . Is s u e : AS I #8 Da t e : 10 / 2 7 / 2 0 0 5 -I l C) — o z. m —I 3h e e t Ti t l e : m 4 — __ _ _ _ _ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ _ _ T II H — — —— = r1 1 r = = l’ h __ _ __ 97 O 5 8 6 . 9 1 4 O U , II —i 11 ‘ 1 U II Ff E A ER1’ PE N I N G ba s I s a r c h © a i r b f t s : m __ i4 i FL U S H , __ _ _ _ _ _ _ _ _ _ _ __ _ _ H U I’ K I IM P N I L ) T 3 5 1 , 4 N II k# 8 Ir __ _ _ I 7: : : fi D I R E D 10 / 2 7 / 2 0 0 5 II U N I’ 1) 0 1 EA 0 F I II I’ : I q1 i , 9 i 1E X I NG f l ‘ __ _ _ _ _ ; I I I 11 (I s T j N G II H I ‘ I ‘ 11 ‘N S L ) P P O l 4 T c U t J O 1 W r S ‘ ii ‘ : : I 11 o ‘ m I I vf l T H I4 C K E F { , RE I I S E C T 0 N II : II : U II I! II 1 II ‘ 11 1 II CD __ _ _ _ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ _ _ _ _ II Ii I I H I I I Ii 3’ ; Sh e e t Ti t l e e c h Fl o o r F ra m i n g ec h Fl o o r Fr a m i n g d Sh e e t No : 1 /4 = 1 O” AX - 2 1 ! vo x : 97 0 . 5 8 6 . 9 1 4 0 fa x : 97 0 . 5 8 6 . 9 1 4 9 ba s l s a r c h © a i r b i t s . c o m () BA S I S Ar c h i t e c t u r e . P. C . Is s u e : AS I # 8 Da t e : 10 / 2 7 / 2 0 0 5 mo o 3” ) Sh e e t Ti t l e : ec h Fl o o r Ca n t i l e v e r Sh e e t No : Ak 2 2 1/ 2 ” PL Y OR OS B GU S S E T 2x 8 KN E E BR A C E c 45 DE G R E E AN G L E 2x 4 BR A C I N G 2x 8 DR O P P E D FO R SO F F 1 T m -I L , ’m H FL U S H MO U N T HA N G E R 14 ” RF P I JO I S T @ 12 ” O. C . 2x 6 ST U D WA L L 2x 1 0 RA F T E R Me c h Fl o o r Ca n t i l e v e r 3/ 4 1 1 = 1 I_ O I l su e : Sl # 8 )a t e : 11 / 1 0 / 2 0 0 5 — —I — D zr I l —I he e t Ti t l e : Dh Fl o o r Ca n t i l e v e r he e t No : X- 2 2 of SI M P S O N U2 6 HA N G E R 2x 8 KN E E BR A C E @ 45 DE G R E E AN G L E , -1 - V P . OF (4 ) 2x 8 DR O P P E D FO R SO F F I T 1,-I 0 1 rn -r O DO >2 14 ” RF P I JO I S T @ 12 ” O. C . ox : 97 0 . 5 8 6 . 9 1 4 0 fa x : 97 0 . 5 8 6 . 9 1 4 9 as i s a r c h i t e c t u r e . c o m () BA S I S Ar c h A t e c t u r e , P. C . 2x 6 SJ D 2x 1 0 RA F T E R 2x 4 BR A C I N G 2x 1 0 LE D G E R Me c h Fl o o r Ca n t i l e v e r 3/ 4 ” = 1 ‘- 0 ”